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A constant force F is pushing a 5 kg mass on a horizontal surface at a constant velocity of 2m/s. The coefficient of friction between the surface and the mass is 0.3. Take g=10m/s^2. If F acts along the direction of motion, the rate at which F is doing work (in watts) is : a)3, b)6, c)10, d)15, e)30 (answer) How do you get this answer? Thanks!
Rate of doing work is known as power and is given by the equation: where is the angle between F and v.Here since F is along the direction of motion therefore and Now, since there is no acceleration the applied force F is used in counteracting the frictional force which is given by: i.e, Substituting and , we get
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