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A constant force F has been applied upon the plank of mass M. Upon the plank, a thin circular wheel of !ass m and radius R has been placed. There is no slipping between plank and wheel. The frictional force upon wheel will be

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10 months ago

Sreehari
13 Points
```							Imagine a basket ball 🏀on a plank.  Now as the plank is pulled by a force F, the ball moves backwards (i.e, opp to the direction of plank's move). This indicates the friction is in the backward. For ball,                   For plank,Fr=ma.                    F-Fr=MaFr is the frictional force and note that both move at same accn but in opp directions.Now divide both eqn and get 'a' rid.  Now solve for Fr. We get Fr= mF/(M+m)  Frictio
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10 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions