Grade 12Mechanics

A constant force F has been applied upon the plank of mass M. Upon the plank, a thin circular wheel of !ass m and radius R has been placed. There is no slipping between plank and wheel. The frictional force upon wheel will be

Question image for A constant force F has been applied upon the plan

Divyanshu Bansal

6 Years agoGrade 12

1 Answer

Sreehari

6 Years ago

Imagine a basket ball 🏀on a plank. Now as the plank is pulled by a force F, the ball moves backwards (i.e, opp to the direction of plank's move). This indicates the friction is in the backward.

For ball, For plank,

Fr=ma. F-Fr=Ma

Fr is the frictional force and note that both move at same accn but in opp directions.

Now divide both eqn and get 'a' rid. Now solve for Fr.

We get Fr= mF/(M+m)

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A constant force F has been applied upon the plank of mass M. Upon the plank, a thin circular wheel of !ass m and radius R has been placed. There is no slipping between plank and wheel. The frictional force upon wheel will be

Divyanshu Bansal

1 Answer

Sreehari

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