a coin kept on a rotatingturntable just slips if it is placed at a distance of 4 cmfrom the centre.if the angular velocity of it is doubled,it will just slip at a distance of
akash rathi , 5 Years ago
Grade 9
2 Answers
Arun
Last Activity: 5 Years ago
w= angular velocity) F= m w^2 r F slip= m w^2 4. --> eqn(1) F slip= m (2w)^2 R2 F slip=4m w^2 R2 --> eqn(2) solving 1 and 2 m w^2 4 = 4 m w^2 R2 so R2 = 1 cm
Khimraj
Last Activity: 5 Years ago
(w= angular velocity)
F= m w^2 r
F slip= m w^2 4. --> eqn(1)
F slip= m (2w)^2 R2
F slip=4m w^2 R2 --> eqn(2)
solving 1 and 2
m w^2 4 = 4 m w^2 R2
so R2 = 1 cm
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