Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A coin is released inside a lift at a height of 2m from the floor of the lift. The height of lift is 10m.the lift is moving with an acceleration of9m/s^2 downward.the time after which the coin will strike with lift is
Net accln of coin is downwards 10-9=1m/s^2 so and distance covered to be 2m so s=ut+1/2at^2 hence 1m=0+1/2×10t^2hence t=root1/5
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -