0

Guest

Courses New

a coin is kept a distance of 10cms from the centre of a turnable table .If the coefficient of static friction is 0.8 find the frequency of rotation of the disc at which the coin will begin to slip

 a coin is kept a distance of 10cms from the centre of a turnable table .If the coefficient of  static friction is 0.8 find the frequency of rotation of the disc at which the coin will begin to slip

Grade:11

1 Answers

Pushkar Prateek
23 Points
7 years ago
Suppose the turn table rotates with  angular (frequency or speed) \omega rad/s. Here, friction will provide the required centripetal force.
The coin will begin to slip when required centripetal force just exceeds maximum possible friction.
So in limiting condition
Centripetal force required for circular motion of the coin just becomes equal to maximum possible friction.
 
0.8mg = m \omega2 0.1
\omega = 4\sqrt{5} rad/s.
 

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More