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A circular turntable is rotating freely about a vertical axis. There is no friction at the axis of rotation. (a) A bug, initially at the center of the turntable, walks out to the rim and stops. How will the angular momentum of the system (turntable plus bug) change? How will the angular velocity of the turntable change? (b) If the bug falls off the edge of the turntable (without jumping), how will the angular velocity of the turntable change?

A circular turntable is rotating freely about a vertical axis. There is no friction at the axis of rotation. (a) A bug, initially at the center of the turntable, walks out to the rim and stops. How will the angular momentum of the system (turntable plus bug) change? How will the angular velocity of the turntable change? (b) If the bug falls off the edge of the turntable (without jumping), how will the angular velocity of the turntable change?
 

Grade:10

1 Answers

Jitender Pal
askIITians Faculty 365 Points
8 years ago
(a) When the bugs walks out to the rim, the rotational inertia of the turntable-bug system will increase. The increase in rotational inertia of the system makes it difficult for the turntable to rotate and therefore its angular speed decreases with time.
(b) If the bugs fall of the turntable without jumping, the rotational inertia of the turntable would decrease. This makes it easier for the turntable to rotate and it start moving with large angular speed, which is in accordance with the law of conservation of angular momentum.

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