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Mechanics

A circular arc of mass m is connected with the help of two massless strings as shown in the figure in vertical plane. About the point P, small oscillations are iven in the plane of the arc. Time Period of the oscillations of SHM will be:
T = 2(pi)*((L*(pi))/( 81/2g ))½
T = 2(pi)*((L*21/2)/( g ))½
T = 2(pi)*((L/21/2)/( g ))½
T = 21/2(pi)*((L)/( g ))½

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Profile image of Datt Patel
8 Years agoGrade
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2 Answers

Profile image of Arun
6 Years ago
The torque equation about the point of suspension is I = Mg(PQ) = Mg(L/2) sin . ]
For small oscillations sin = and moment of inertia about the point of suspension is I= 
3
ML 
2
 
​ 
 . Substituting the values, we get  
dt 
2
 
2
 
​ 
 =−(3g/2L). 
 
Thus, time period T = 2(2L/3g) 
Profile image of Vikas TU
6 Years ago
Dear student 
The above explanation is not properly explained 
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