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A chain consisting of five links, each with mass 100 g, is lifted vertically with a constant acceleration of 2.50 m/s 2 , as shown in Fig. 3-35. Find (a) the forces acting between adjacent links, (b) the force F exerted on the top link by the agent lifting the chain, and (c) the net force on each link.
Dear student,The answer to your question will be a)On each link the force fromUpward link = 1.23, 2.46, 3.69, 4.92 respectively from bottom to top (in N)Downward link = 0, 1.23, 2.46, 3.69 respectively from bottom to top ( in N) b)6.15 N c)0.25 NFor complete solution refer to the above answer Thanks and regards,Kushagra
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