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A certain string can withstand a maximum tension of 9.2 lb without breaking. A child ties a 0.82-lb stone to one end and, holding the other end, whirls the stone in a vertical circle of radius 2.9 ft, slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b)What is the speed of the stone as the string breaks?
A certain string can withstand a maximum tension of 9.2 lb without breaking. A child ties a 0.82-lb stone to one end and, holding the other end, whirls the stone in a vertical circle of radius 2.9 ft, slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b)What is the speed of the stone as the string breaks?

```
5 years ago

396 Points
```							(a)When the stone is at the bottom, the weight of the stone is in opposite direction with that to tension, and this is where the tension in the string is maximum.Therefore, the string will break when the stone reaches the bottom.Therefore, the speed with which the stone rotates when the string breaks up is 31 ft/s .
```
5 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions