MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A certain string can withstand a maximum tension of 9.2 lb without breaking. A child ties a 0.82-lb stone to one end and, holding the other end, whirls the stone in a vertical circle of radius 2.9 ft, slowly increasing the speed until the string breaks. (a) Where is the stone on its path when the string breaks? (b)What is the speed of the stone as the string breaks?

5 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
							(a)
When the stone is at the bottom, the weight of the stone is in opposite direction with that to tension, and this is where the tension in the string is maximum.

Therefore, the string will break when the stone reaches the bottom.


236-2235_1.PNG
Therefore, the speed with which the stone rotates when the string breaks up is 31 ft/s .

5 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details