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         A carrom board( 5ft*5ft) has the queen at the centre,the queen hit by the striker moves to front edge ,rebounds and goes in hole behind the striking line.Find the magnitude of displacement of queen a)from centre to front edge b)fron centre to hole.  please send the paper solution
5 months ago

Saurabh Koranglekar
3161 Points
							Dear studentFrom centre to the front edge may require more informationFrom center to hole is (sqrt(2.5^2)+(2.5^2))Ie 5/(sqrt(2))Regards

5 months ago
Khimraj
3008 Points
							The starting point of the queen was at the centre of the board. Since the board is a square, this means that the queen was at the centre of the diagonal of the square. Since the queen ended up in one of the pockets, its final position is at a vertice of the square. The displacement will be the distance between the initial and final position. The distance of any two opposite vertices (diagonal length) of a square is always a root 2, where a is the length of side. But here, since the queen is at the centre of diagonal, the distance will be half the diagonal. So the displacement will be 5$\sqrt{2}$/2

5 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions