A car travels equal distances in the same direction with velocities 60km/h,20km/h and 10km/h respectively.The magnitude of average velocity of the car over the whole journey of motion

Question

Aryan Rao · Answer

A car is travelling equal distances without changing its direction means the sign of velocity will not be changed avg velocity=total displacement/total time 60+20+10/3=30km/h

Khimraj · Answer

let equal distance is x then avg velocity=total displacement/total time = 3x/(x/60 + x/20 + x/10) = 18km/h Hope it clears.

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A car travels equal distances in the same direction with velocities 60km/h,20km/h and 10km/h respectively.The magnitude of average velocity of the car over the whole journey of motion

A car travels equal distances in the same direction with velocities 60km/h,20km/h and 10km/h respectively.The magnitude of average velocity of the car over the whole journey of motion

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A car travels equal distances in the same direction with velocities 60km/h,20km/h and 10km/h respectively.The magnitude of average velocity of the car over the whole journey of motion

A car travels equal distances in the same direction with velocities 60km/h,20km/h and 10km/h respectively.The magnitude of average velocity of the car over the whole journey of motion

2 Answers

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