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A car traveling at 60 km/h overtakes another car traveling at 42 km/h. Assuming each car to be 5m long find the time taken during the overtake and the total ROAD distance used for the overtake.
A car traveling at 60 km/h overtakes another car traveling at 42 km/h. Assuming each car to be 5m long find the time taken during the overtake and the total ROAD distance used for the overtake.

```
3 years ago

Arun
25768 Points
```							For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m (5m for catching up and 5m for getting clear ahead) therefore Srel = 10 m       Vrel = 60-42 = 18km/hr = 5 m/s       Relative acceleration = 0 .since both are moving with constant velocities. Now using relative motion,           S = Vrel × t therefore time ,t = S / Vrel = 10/5 = 2s Distance is   60 × 5/18 × 2 = 100/3 = 33.33 mhence total road distance used for overtake = 5 + 33.33 = 38.33 m
```
3 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions