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A car traveling at 60 km/h overtakes another car traveling at 42 km/h. Assuming each car to be 5m long find the time taken during the overtake and the total ROAD distance used for the overtake. A car traveling at 60 km/h overtakes another car traveling at 42 km/h. Assuming each car to be 5m long find the time taken during the overtake and the total ROAD distance used for the overtake.
For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m (5m for catching up and 5m for getting clear ahead) therefore Srel = 10 m Vrel = 60-42 = 18km/hr = 5 m/s Relative acceleration = 0 .since both are moving with constant velocities. Now using relative motion, S = Vrel × t therefore time ,t = S / Vrel = 10/5 = 2s Distance is 60 × 5/18 × 2 = 100/3 = 33.33 mhence total road distance used for overtake = 5 + 33.33 = 38.33 m
For the car with 60kmph to overtake the first car it should travel a relative distance of 10 m
(5m for catching up and 5m for getting clear ahead)
therefore Srel = 10 m
Vrel = 60-42 = 18km/hr = 5 m/s
Relative acceleration = 0 .since both are moving with constant velocities.
Now using relative motion, S = Vrel × t
therefore time ,t = S / Vrel = 10/5 = 2s
Distance is 60 × 5/18 × 2 = 100/3 = 33.33 m
hence total road distance used for overtake = 5 + 33.33 = 38.33 m
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