A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

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Arun · Answer

Dear KArthik S=(ft^2)/2 V.=squere root of(2Sf) During retardation S2=2S During constant velocity 15S -3S = 12S = vo . '' .S= (ft^2)/72

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A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

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A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

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