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A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

Karthik , 7 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear KArthik
 
 

S=(ft^2)/2

V.=squere root of(2Sf)

During retardation S2=2S

During constant velocity  15S -3S = 12S = vo

. '' .S= (ft^2)/72

Last Activity: 7 Years ago
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