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A car starting from rest accelerates at rate a through distance d,then continues at constant speed for time t,decelerates at the rate of a/2 to come to rest .if the total distance traveled is 15d,then d equals to

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2 years ago

Arun
25768 Points
```							Dear KArthik  S=(ft^2)/2V.=squere root of(2Sf)During retardation S2=2SDuring constant velocity  15S -3S = 12S = vo. '' .S= (ft^2)/72
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions