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`        A car of mass 1000kg moves at a constant speed of 20m/sec up an incline .assume that the frictional force is 200N and that sin=1/20 ,find the power developed by the engine`
one year ago

Ojas
20 Points
```							14000 watts. As Power = F.V And v = 20m/sF is force  given by engine to overcome forces trying to stop carAs v is constant so net force by engine is equal to force trying to stop itNamely Gravity and frictionF = mgsinx + friction = 100000/20 + 200 = 700Power = 700*20 = 14000
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions