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Grade 10Mechanics

A car moves at a constant speed on a straight but hilly road. One section has a crest and dip of the same 250-m radius; see Fig. (a) As the car passes over the crest, the normal force on the car is one-half the 16-kN weight of the car. What will be the normal force on the car as it passes through the bottom of the dip? (b) What is the greatest speed at which the car can move without leaving the road at the top of the hill? (c) Moving at the speed found in (b), what will be the normal force on the car as it moves through the bottom of the dip?

Hrishant Goswami

11 Years agoGrade 10

1 Answer

Jitender Pal

11 Years ago

Therefore, the normal force experienced by the car when it passes through trough is 24 kN .

Round off to two significant figures,
v = 50 m/s
Therefore, the velocity with which the car passes the top of the hilly road is 50 m/s .
(c)
Substitute 16 kN for W in equation N = 2W ,
N = 2 (16 kN)
= 32 kN
Therefore, the normal force experienced by the car when it passes through trough is 32 kN.

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