Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A car moves at a constant speed on a straight but hilly road. One section has a crest and dip of the same 250-m radius; see Fig. (a) As the car passes over the crest, the normal force on the car is one-half the 16-kN weight of the car. What will be the normal force on the car as it passes through the bottom of the dip? (b) What is the greatest speed at which the car can move without leaving the road at the top of the hill? (c) Moving at the speed found in (b), what will be the normal force on the car as it moves through the bottom of the dip?
Therefore, the normal force experienced by the car when it passes through trough is 24 kN .Round off to two significant figures,v = 50 m/sTherefore, the velocity with which the car passes the top of the hilly road is 50 m/s .(c)Substitute 16 kN for W in equation N = 2W ,N = 2 (16 kN) = 32 kNTherefore, the normal force experienced by the car when it passes through trough is 32 kN.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -