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A Car is travelling on a straight road. The maximum velocity the car can attain is 24 m/s . The maximum acceleration and decleration it csn attain are 1 & 4 m/s2 respectively . What will be the shortest time the car takes from rest to rest in a distance of 200 m.
please check acceleration, decleration, max velocity and distance value and confirm it.…................................................................................................
HELLO! Maximum velocity that the car can attain is 24 m/s, so v = 24 m/s.Maximum acceleration a = 1 m/s2Maximum retardation = 4 m/s2Distance given = 200m. Car starts from rest and ends by going to rest. Now, time required by the car to start from rest and accelerate to 24 m/s at a rate of 1m/s2 is:v = u + at=> 24 = 0 + 1xt=> t = 24 seconds. Distance covered in this 24 seconds:S = ut + ½ at2=> S = 0 + ½ x 1 x 24 x 24=> S = 288m, which is coming greater than the given value. So, it is proved that there’s something incorrect in the question.The question, hence, is invalid.
Is it 22.36 (10/5).. .. . .. .. .. .. .. .. ... ... .. .. .. .. .... ... . .. . .. . .. .. ... .. .. ... .. ... .. .. .. ........ .. ... ... .... ...... ... .... .. .. .. .. .. .. .. .
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