Rajdeep
Last Activity: 6 Years ago
HELLO!
Maximum velocity that the car can attain is 24 m/s, so v = 24 m/s.
Maximum acceleration a = 1 m/s2
Maximum retardation = 4 m/s2
Distance given = 200m.
Car starts from rest and ends by going to rest.
Now, time required by the car to start from rest and accelerate to 24 m/s at a rate of 1m/s2 is:
v = u + at
=> 24 = 0 + 1xt
=> t = 24 seconds.
Distance covered in this 24 seconds:
S = ut + ½ at2
=> S = 0 + ½ x 1 x 24 x 24
=> S = 288m, which is coming greater than the given value.
So, it is proved that there’s something incorrect in the question.
The question, hence, is invalid.
