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A Car is travelling on a straight road.  The maximum velocity the car can attain is 24 m/s . The maximum acceleration and decleration it csn attain are 1 & 4  m/s2 respectively . What will be the shortest time the car takes from rest to rest in a distance of 200 m.
one year ago

Answers : (3)

Khimraj
3008 Points
							
please check acceleration, decleration, max velocity and distance value and confirm it.
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one year ago
Rajdeep
229 Points
							
HELLO!
 
Maximum velocity that the car can attain is 24 m/s, so v = 24 m/s.
Maximum acceleration a = 1 m/s2
Maximum retardation = 4 m/s2
Distance given = 200m.
 
Car starts from rest and ends by going to rest.
 
Now, time required by the car to start from rest and accelerate to 24 m/s at a rate of 1m/s2  is:
v = u + at
=> 24 = 0 + 1xt
=> t = 24 seconds.
 
Distance covered in this 24 seconds:
S = ut + ½ at2
=> S = 0 + ½ x 1 x 24 x 24
=> S = 288m, which is coming greater than the given value.
 
So, it is proved that there’s something incorrect in the question.
The question, hence, is invalid.
one year ago
Advaith
13 Points
							
Is it 22.36 (10/5)
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one year ago
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