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A car is travelling at the rate of 54kmph . Suddenly the brakes are applied causing tyres to skid .How far will the car travel before coming to rest if coefficient of friction is 0.2 and g is equal to 9.8
Frictional force = u(coefficient of friction) * F(Normal force) We know, Energy = Force * Displacement therefore, Frictional energy = u * F * S(Displacement) Similarly, we know, kinetic energy = ½ [m * v^2] Since energy is same throughout ½ [m * v^2] = u * F * S ½ [m * v^2] = u * (m*g) *S { F = m*g } ½ v^2 = u * g * S S = v^2 / (2 * u * g) Substituting the values: v = 15 m/s u = 0.2 g = 9.8 m/s^2 S = [(15)^2] / [2 * (0.2) * (9.8)] S = 225 / 3.92 S = 57.39 m S ~ 57.4 m So the car will travel 57.4 meter? before coming to rest
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