Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A car is traveling with a velocity v on a circular road of radius r. If it is decreasing it`s speed at the rate of a, then the magnitude of resultant acceleration will be.......`
2 years ago

Arun
23506 Points
```							Dear student   The instantaneous acceleration ar pointing towards the center of the circle is called radial acceleration or centripetal acceleration.                      The radial component causes a change in direction and its magnitude is given by ar = v2/r, where r is the radius of curvature at the point in question. The tangential component causes a change in speed and its magnitude is given by at = dv/dt = a m/sec2 (given) The tangential acceleration of the car has a constant magnitude of at = a m/sec2 The components ar and at are perpendicular to each other and the magnitude of a is given by resultant accln. a2 = ar2 + at2                          resultant accln. (ares)         =[ a2+(v2/r)2 ]1/2                                                                       =[ a2 +(v4/r2) ]1/2 RegardsArun(askIITians forum expert)
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions