badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

A car is negotiating a curved road of radius r. The road is banked at an angle @.The coefficient of friction between the tyres of the car and the road is u. the maximum safe velocity on ths road is what???

2 years ago

Answers : (1)

Lennon
16 Points
							The centrifugal force is the force moving outward. The frictional is the force moving inwards to prevent the car from slipping out of the road.Centrifugal force=centripetal force=mv^2/rFrictional force= coefficient of friction x normal force NTherefore,the frictional force must be larger than the centrifugal force to hold it.But,the maximum centrifugal force must be equal to the frictional force. If it exceeds the frictional force it slips.So, we getF(c)max=fmv^2/r=μNmv^2=uNrv^2=uNr/mvmax=√(uNr/m)
						
2 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details