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A car is driven east for a distance of 50 km , then north for 30 km ,and then in a direction 30° east of north for 25 km. Skitch the vector diagram and determine (a) the magnitude and (b) the angle of the car`s total displacement from its starting point.
Dear student x = 50 + 25 cos 30 = 50 + 21.65 = 71.65 km y = 30 + 25 sin 30 = 30 + 12.5 = 42.5 km a) magnitude L ^2 = √ 71.65 ^2 + 42.5 ^2 = √6940 ---- L = 83.306 km b) tg α = 42.5/ 71.65 = 0.59316---- α = 30.675 ° RegardsArun (askIITians forum expert)
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