Vikas TU
Last Activity: 7 Years ago
Dear Student,
For the same range R of a projectile the angle of projection can be and 90-
Height of a projectile when angle of projection is = h= u2sin2/2g (u=initial velocity)
Height of projectile when angle of projection is 90- = h*=u2sin2(90-)/2g = u2cos2/2g
usual formula of range = u2sin2/g
hxh* = u4sin22/16g2
=>√(hXh^* ) = u2sin2/4g
=>4√(hXh^* ) = u2sin2/g
=>R=4√(hXh^* ).
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)
