Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A bullet travelling with a velocity of 16 m/s penetrates a tree trunk and comes to rest in 0.4 m. Find the time taken during the retardation.

A bullet travelling with a velocity of 16 m/s penetrates a tree trunk and comes to rest in 0.4 m. Find the time taken during the retardation.

Grade:11

3 Answers

Kevin Nash
askIITians Faculty 332 Points
7 years ago
Sol. u = 16 m/s (initial), v = 0, s = 0.4 m. Deceleration a = (v^2-u^2)/2s = -320 m/s2. Time = t = (V -u)/a = (0-16)/(-320 ) = 0.05 sec.
Sai Sriker Reddy Kuskuntla
34 Points
4 years ago
u=16 m/s v=0S=0.4A=(v*v)-(u*u)/2A=0-256/0.8=-320t =(v-u)/a= -16/-320=0.05 secondTime taken during its motion in trunk=0.05 secondRetradation =320 m/s
Sakshi Kumari
24 Points
3 years ago
Initial velocity= u= 16 m/s
distance covered = S=  0.4 m
Final velocity=v= 0 m/s 
the equation of motion;
v²=u²+2aS
0=16²+2 x a x 0.4 
a=-16²/0.8  
a=-320 m/s
As it carries a negative sign it represent retardation. 
Time taken during the retardation is given by the equation;
 v=u+at 0= 16-320 x t   
t=16/320 
t=1/20 
t=0.05 s
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free