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`         A bullet travelling with a velocity of 16 m/s penetrates a tree trunk and comes to rest in 0.4 m. Find the time taken during the retardation.`
5 years ago

```							Sol. u = 16 m/s (initial), v = 0, s = 0.4 m.
Deceleration a = (v^2-u^2)/2s = -320 m/s2.
Time = t = (V -u)/a = (0-16)/(-320 ) = 0.05 sec.

```
5 years ago
```							u=16 m/s v=0S=0.4A=(v*v)-(u*u)/2A=0-256/0.8=-320t =(v-u)/a= -16/-320=0.05 secondTime taken during its motion in trunk=0.05 secondRetradation =320 m/s
```
2 years ago
```							Initial velocity= u= 16 m/sdistance covered = S=  0.4 mFinal velocity=v= 0 m/s the equation of motion;v²=u²+2aS0=16²+2 x a x 0.4 a=-16²/0.8  a=-320 m/sAs it carries a negative sign it represent retardation. Time taken during the retardation is given by the equation; v=u+at 0= 16-320 x t   t=16/320 t=1/20 t=0.05 s
```
one year ago
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