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`        A bullet of weight 50 m is fired into a body of weight 5 kg, which is suspended by a string 1 m long. Due to this impact, the 5 kg. body swings through an angle of 30 deg from the vertical. Calculate the velocity of the bullet.`
one year ago

Baijnath
18 Points
```							Since bullet is moving with some velocity...so it has KE=1/2mv^2And it displace bigger block . .thr throan angle of 30° …Draw fugfig...U will fing that.....PE of block is... changed...i.e Mgh...(With hight  L(1-cos©) )So equate...KE And PE...i.e 1/2mv^2=MgL(1-cos©)......(.1)U will get the answerHope you understand 😊😊😊😊😊😊😊
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions