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A bullet of mass m moving with velocity v strikes a suspended wooden block of masss M. If the block rise to height h, then the initial velocity v of the bullet must have been??

Kuldeep Pal , 8 Years ago
Grade 12th pass
anser 1 Answers
Shaswata Biswas

Last Activity: 8 Years ago

From law of conservation of mechanical energy. At the lower mostt point, KE = 0.5mv^2, PE = 0. At the highest point KE = 0, PE = mgh. These are equal. The we get, 0.5mv^2=mgh => v=root(2gh).

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