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A bullet of mass a and velocity b is fired into a large block of mass c. The final velocity of the system is?
Applying conservation of linear momentum, Initial momentum is ab.Final momentum is (a+c)*final velocity.There for final velocity=ab/(a+c)[momentum before collision is equal to momentum after collision]
As the external force is zero so we can apply conservation of momentum lawSoa*b = (a+c)*vThen v = ab/(a+c) m/sHope it clears. If you like answer then please approve it.
Mass of bullet=a (m1)initial velocity of bullet=b (u1)Mass of large block=c (m2)Initial velocity of large block=0 (u2)M1v2 + m2u2= v(m1+m2)(a*b)+(c*0)=v(a+c)ab=v(a+c)V=ab (a+c)
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