Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
A bullet of mass a and velocity b is fired into a large block of mass c. The final velocity of the system is?
Applying conservation of linear momentum, Initial momentum is ab.Final momentum is (a+c)*final velocity.There for final velocity=ab/(a+c)[momentum before collision is equal to momentum after collision]
As the external force is zero so we can apply conservation of momentum lawSoa*b = (a+c)*vThen v = ab/(a+c) m/sHope it clears. If you like answer then please approve it.
Mass of bullet=a (m1)initial velocity of bullet=b (u1)Mass of large block=c (m2)Initial velocity of large block=0 (u2)M1v2 + m2u2= v(m1+m2)(a*b)+(c*0)=v(a+c)ab=v(a+c)V=ab (a+c)
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -