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A bullet of mass a and velocity b is fired into a large block of mass c.The final velocity of the system is?

Surendra , 6 Years ago
Grade 9
anser 3 Answers
ABHIJITHU S

Last Activity: 6 Years ago

Applying conservation of linear momentum,
 Initial momentum is ab.
Final momentum is (a+c)*final velocity.
There for final velocity=ab/(a+c)[momentum before collision is equal to momentum after collision]

Khimraj

Last Activity: 6 Years ago

As the external force is zero so we can apply conservation of momentum law
So
a*b = (a+c)*v
Then v = ab/(a+c) m/s
Hope it clears. If you like answer then please approve it.

Kiran

Last Activity: 6 Years ago

Mass of bullet=a (m1)
initial velocity of bullet=b (u1)
Mass of large block=c (m2)
Initial velocity of large block=0 (u2)
M1v2 + m2u2= v(m1+m2)
(a*b)+(c*0)=v(a+c)
ab=v(a+c)
V=ab
    (a+c)
 
 
 

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