A bullet of mass 25g was moving at the rate of 500ms-1. After passing through a solid block, it continued to move at the rate of 100ms-1. How much work the bullet had to do in passing the block.

Question

Shailendra Kumar Sharma · Answer

The work done by the bullet can be given by the change in kinetic energy... W=K2-K1 =1/2m(V 2 2 -V 1 2 ) =0.5X(.025)*( 500 2 – 100 2 ) =3000Joules

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A bullet of mass 25g was moving at the rate of 500ms-1. After passing through a solid block, it continued to move at the rate of 100ms-1. How much work the bullet had to do in passing the block.

A bullet of mass 25g was moving at the rate of 500ms-1. After passing through a solid block, it continued to move at the rate of 100ms-1. How much work the bullet had to do in passing the block.

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A bullet of mass 25g was moving at the rate of 500ms-1. After passing through a solid block, it continued to move at the rate of 100ms-1. How much work the bullet had to do in passing the block.

A bullet of mass 25g was moving at the rate of 500ms-1. After passing through a solid block, it continued to move at the rate of 100ms-1. How much work the bullet had to do in passing the block.

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