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A bullet of mass 0.04kg moving with a speed of 90 m/s enters a heavy wooden block and is stopped after a distance of 60 cm.What is the average force exerted by block on bullet?

A bullet of mass 0.04kg moving with a speed of 90 m/s enters a heavy wooden block and is stopped after a distance of 60 cm.What is the average force exerted by block on bullet?

Grade:12th pass

1 Answers

Adarsh
768 Points
6 years ago
 
we will calculate the retardation of bullet after hitting wooden block.
v2-u2=2as
by using this we will get a=9750m/s2.
now force = mass x acceleration = 9750 x 0.04 =390 N
hope this will help ..
if there is any more doubt in this question then let me know i will happy to help you ..
Thanks and Regards
Adarsh

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