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`        A bullet is fired vertically into the air from the top of a building and reaches a height of 1600 m above the top of the building. It then falls to the ground below. The total time of flight is 38.0 s.     (a) Calculate the speed at which the bullet leaves the gun.     (b) From what height above the ground is the bullet fired?     (c) Calculate the speed of the bullet when it hits the ground. `
one year ago

Himanshu Rathour
119 Points
```							Let height of building is h, velocity with which bullet is fired is vNow0=u²-2g(1600)u=177.08m/s0=v-gtt=177.08/9.8≈18sTotal time of flight =38 sTime of descent =38-18=20sS=0t+1/2(9.8)20²S=1960mHeight of building=1960-1600=360mSpeed with which bullet hits ground isV=9.8*20=196m/s
```
one year ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions