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A bullet fired from a point on horizontal ground at an angle 30 degree with the horizontal hits the ground 3 km away. By adjusting the angle of projectio, can one hope to hit a target 5 km away?
Solution:Given that:Range, R = 3 kmAngle of projection, θ = 30°Acceleration due to gravity, g = 10 m/sHorizontal range for the projection velocity u , is given by the relation:u2/g=2The maximum range (R ) is achieved by the bullet when it is fired at an angle of 45° with the horizontal, that is,Rmax=u2/gOn comparing equations (i) and (ii), we get:Rmax=3=3.46kmHence, the bullet will not hit a target 5 km away
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