A boy throws aball in air in such a manner that when the ball is in its max height, he throws a anothervball after a time diif of 1 sec. What will be the height atained by them

Question

Vikas TU · Answer

Time difference that is 1 sec. That means the time of flight is 2 sec. Hence, T = 2 = 2u/g u = 10 m/s. H =u^2/2g = > 100/20 = 5 meter.

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A boy throws aball in air in such a manner that when the ball is in its max height, he throws a anothervball after a time diif of 1 sec. What will be the height atained by them

A boy throws aball in air in such a manner that when the ball is in its max height, he throws a anothervball after a time diif of 1 sec. What will be the height atained by them

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A boy throws aball in air in such a manner that when the ball is in its max height, he throws a anothervball after a time diif of 1 sec. What will be the height atained by them

A boy throws aball in air in such a manner that when the ball is in its max height, he throws a anothervball after a time diif of 1 sec. What will be the height atained by them

1 Answers

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