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A boy throws a ball from shoulder height level at an initial velocity of 30 m/s. Spending 4.8s in air, the ball is caught by another boy as the same shoulder height level. What is the angle of projection? a) 37 b) 30 c) 53 d) 60

Nikita Singh , 8 Years ago
Grade 12th pass
anser 1 Answers
Arun
Dear Nikita
 
As we know
t = 2* u * sin@/g
 4.8= 2* 30 * sin@/10
4.8 = 6 sin@
48/60 = sin@
Sin@ = 4/5
Hence @ = 53°
 
Regards
Arun (askIITians forum expert)
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Last Activity: 8 Years ago
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