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```
A boy throws a ball,B from top of tower down at velocity 20 m/s and another boy from the ground level of tower throws a ball,A up at 5m/sec.Height of tower is 100m.Find the time when balls will collide? Why time when B will meet A is t=distance/velocity.?

```
2 years ago

Eshan
2095 Points
```							Dear student,Relative velocity of both the balls=$20m/s+5m/s=25m/s$Relative acceleration=$0m/s^2$Initail distance between them 100m.Hence time taken to collide=$\dfrac{100m}{25m/s}=4s$
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions