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Grade: 11
        
A boy is running along positive x axis with 8m/s . While running he manages to throw a stone in a plane perpendicular to his direction of running with velocity 12m/s at an angle 30 degree with vertical. Find the speed of the stone at the highest point of the trajectory .
8 months ago

Answers : (3)

Payal
17 Points
							
At the Highest point of the trajectory, vertical component of velocity  becomes zero but the horizontal component remains constant i.e. 12sin30 i.e 6m/s.
.  
8 months ago
Varad Raut
9 Points
							
As Cos 60 degree is half so 12cos60 is 6 and it has already speed of 8 metre per second in x-axis hence 8 + 6 is 14 correct answer should be 14
8 months ago
Payal
13 Points
							The boy thrw the ball at 12m/s wrt to ground its not mentioned anywhere that h
						
8 months ago
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Course Features

  • 110 Video Lectures
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  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


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