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A boy is hanging from a horizontal branch of a tree.The tension in his arms will be maximum when the angle between his arms will be what????

A boy is hanging from a horizontal branch of a tree.The tension in his arms will be maximum when the angle between his arms will be what????     

Grade:11

2 Answers

Arun
25750 Points
6 years ago
The resultant of tensions in the arm must be equal to weight F (= mg)
Hence
F² = P² +P² + 2P² cos @
F² = 2P²( 1+ cos@)
P² = F²/2(1+cos @)
P is max when (1+ cos@ ) is min
 Cos @ = -1
@ = 180 ° is not possible
Hence cos @ = -1/2
Hence
@ = 120 °
Anurag
11 Points
5 years ago
Let tension be t so 
Angle between arms be @ and @
F=mg
So by resolution we get
2rcos@=mg
r=mg/2cos@
Diffrenciate it and ill get ans as 120'

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