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A boy is hanging from a horizontal branch of a tree.The tension in his arms will be maximum when the angle between his arms will be what????
The resultant of tensions in the arm must be equal to weight F (= mg)HenceF² = P² +P² + 2P² cos @F² = 2P²( 1+ cos@)P² = F²/2(1+cos @)P is max when (1+ cos@ ) is min Cos @ = -1@ = 180 ° is not possibleHence cos @ = -1/2Hence@ = 120 °
Let tension be t so Angle between arms be @ and @F=mgSo by resolution we get2rcos@=mgr=mg/2cos@Diffrenciate it and ill get ans as 120'
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