A boy is dropped from a height of 250 m, and simultaneously another body is dropped from a height of 200 m. What is the difference in heights after they have fallen for 5 seconds?

If thought logically, they both accelerate at the same rate(9.8) and start with same initial velocity(0) and dropped at the same time. Hence difference in height after any number of seconds= 250m-200m=50m. If you need the answer the physics way, here it is-- u1=u2=0,t=5s,g=9.8ms-1➡by S=ut+1/2at2 , S1=0+9.8×5×5/2=122.5m & S2=0+9.8×5×5/2=122.5m. Therefore distance of boy from ground=250-122.5=127.5m & distance of object from ground=200-122.5=77.5m.🔨 Therefore difference between them=127.5-77.5=50m.