A box of mass 1 kg rests on a frictionless inclined plane which is at an angle of 30◦ to the horizontal plane. Find the constant force that needs to be applied parallel to the incline to move the box down the incline with an acceleration of 1m/s$^2$.

Question

Satyam Agarwal · Answer

Component of mg parallel to the incline= mgsin30 = 5 N Let the force F acts upward parallel to the incline. Now, 5N -F = M*a F = 5- 1*1 = 4 N.

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A box of mass 1 kg rests on a frictionless inclined plane which is at an angle of 30◦ to the horizontal plane. Find the constant force that needs to be applied parallel to the incline to move the box down the incline with an acceleration of 1m/s$^2$.

A box of mass 1 kg rests on a frictionless inclined plane which is at an angle of 30◦ to the horizontal plane. Find the constant force that needs to be applied parallel to the incline to move the box down the incline with an acceleration of 1m/s$^2$.

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A box of mass 1 kg rests on a frictionless inclined plane which is at an angle of 30◦ to the horizontal plane. Find the constant force that needs to be applied parallel to the incline to move the box down the incline with an acceleration of 1m/s$^2$.

A box of mass 1 kg rests on a frictionless inclined plane which is at an angle of 30◦ to the horizontal plane. Find the constant force that needs to be applied parallel to the incline to move the box down the incline with an acceleration of 1m/s$^2$.

1 Answers

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