badge image

Enroll For Free Now & Improve Your Performance.

×
User Icon
User Icon
User Icon
User Icon
User Icon

Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 11

                        

a bomb at rest explodes into three fragments.two fragments fly off at right angles to each other.these two fragments:the one with mass 2kg moves with a speed of 12m/s,and the other onewith mass 1kg moves with 8m/s.the speed of the third fragment is 20m/s,then calculate its mass

3 years ago

Answers : (1)

sourav mittal
5 Points
							
if the bomb is at rest , its velocity is 0 , hence its mommentumis 0
now , its explodes into 3 parts …
1st  part : mass=2kg, v1=-12 m/s( – sign is due to opposite direction , you can also take v1 and v2 +ve  and  v3 -ve)
2nd part : mass= 1kg; v2 =- 8m/s
3rd part : v3 = 20m/s
initially bomb was at rest , therefore its initial momentum =0;
as we know momtum remains conserved,therefore initial momentum = final momentum
0=2*-12+1*-8+m*20
32=20m
m=1.6kg
 
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 101 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 110 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details