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Grade: 9
        
a bolck lying ona inclined plane has a weight os 50N .It is just begins to slide down when the inclination of plane with the horizontal is 30 The value of U s is
 
one month ago

Answers : (4)

Arun
21973 Points
							
Dear Uday
 
I didn’t get U. Please elaborate it or you can also attach an image. I will be happy to help you.
one month ago
Khimraj
3008 Points
							

The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.

Hence in this situation, frictional force = µsN

Balancing the forces :

N = W cos 30º

µsN = W sin 30º

µs W cos 30º = W sin 30º

µs = 1/\sqrt{3}

one month ago
Khimraj
3008 Points
							

The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.

Hence in this situation, frictional force = µsN

Balancing the forces :

N = W cos 30º

µsN = W sin 30º

µs W cos 30º = W sin 30º

µs = 1/\sqrt{3}

one month ago
aswanth nayak
63 Points
							

Dear Student,

The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.

Hence in this situation, frictional force = µsN

Balancing the forces :

N = W cos 30º

µsN = W sin 30º

µs W cos 30º = W sin 30º

µs = 1/\sqrt{3}

 

Hope it helps you

Regards

yesterday
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