Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
        a bolck lying ona inclined plane has a weight os 50N .It is just begins to slide down when the inclination of plane with the horizontal is 30 The value of U s is
3 months ago

Arun
22587 Points
							Dear Uday I didn’t get U. Please elaborate it or you can also attach an image. I will be happy to help you.

3 months ago
Khimraj
3008 Points
							The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$

3 months ago
Khimraj
3008 Points
							The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$​

3 months ago
aswanth nayak
66 Points
							Dear Student,The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$ Hope it helps youRegards

2 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions