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        a bolck lying ona inclined plane has a weight os 50N .It is just begins to slide down when the inclination of plane with the horizontal is 30 The value of U s is
one year ago

Arun
24739 Points
							Dear Uday I didn’t get U. Please elaborate it or you can also attach an image. I will be happy to help you.

one year ago
Khimraj
3007 Points
							The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$

one year ago
Khimraj
3007 Points
							The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$​

one year ago
aswanth nayak
100 Points
							Dear Student,The block reaches the point of sliding when the plane makes an angle of 30º with the horizontal.Hence in this situation, frictional force = µsNBalancing the forces :N = W cos 30ºµsN = W sin 30ºµs W cos 30º = W sin 30ºµs = 1/$\sqrt{3}$ Hope it helps youRegards

11 months ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions