A bodyis thrown vertically upward with velocity 10 m/s. When it reach to the point it loses its 25% kinetic energy . Then find the distance of the point from the ground .

Question

Vikas TU · Answer

From the enrgy conservation principle, Taking the reference from ground, 0.5*m*v^2 + 0 = mgh + 0.75*(0.5mv^2) m gets cancelled. solvee for h that would be the distance from ground.

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A bodyis thrown vertically upward with velocity 10 m/s. When it reach to the point it loses its 25% kinetic energy . Then find the distance of the point from the ground .

A bodyis thrown vertically upward with velocity 10 m/s. When it reach to the point it loses its 25% kinetic energy . Then find the distance of the point from the ground .

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A bodyis thrown vertically upward with velocity 10 m/s. When it reach to the point it loses its 25% kinetic energy . Then find the distance of the point from the ground .

A bodyis thrown vertically upward with velocity 10 m/s. When it reach to the point it loses its 25% kinetic energy . Then find the distance of the point from the ground .

1 Answers

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Other Related Questions on Mechanics

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