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a body travels for 15 sec starting from rest with constant acclerations if it travels distance s1 s2 s3 in the first five second second five seconds and next five seconds respectively the relation between s1,s2 and s3 is

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2 years ago

Arun
24737 Points
```							here the acceleration and the time interval in all three parts is the sameย part 1the body starts from rest with acceleration 'a' and attains a velocity 'v1' after t = 5 secondsso,s1ย = 0 + (1/2)at2ย ย (1)andย v1ย = 0 + atorv1ย = at ย (2)ย part 2the body has an initial velocity v1ย and accelerates to v2ย after t = 5secondsso,s2ย = v1t + (1/2)at2or from eq (2)s2ย = at.t + (1/2)at2thus,s2ย = (3/2)at2ย ย ย ย (3)andv2ย = v1ย + atorv2ย = at + at = 2at ย (4)ย part 3the body has an initial velocity 'v2' and accelerates to 'v3' after t = 5 secondsso,s3ย = v2t + (1/2)at2or from equation (4)s3ย = 2at.t + (1/2)at2sos3 = (5/2)at2ย ย ย ย ย (5)ย now from equations (1), (3) and (5) we confirm thats1ย = s2/3ands1ย = s3/5ands2/s3ย = 3/55s2ย = 3s3ors2/3= s3/5thus, finally we gets1ย = s2/3 = s3/5
```
2 years ago
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• 110 Video Lectures
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions