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let initial velocity = u & accleration is a then
distance travelled in 5 sec = S7
using , s=ut + at2/2
S7 = 7u + a49/2
= 7u+24.5 a
distance covered in 2 sec = S2 = 2u + 4a/2
=2u+2a = 200 (given)
u+a = 100 ........................1
now distance covered in 2 to 6 sec is given 220cm
S7-200 = 220
7u + 24.5a = 420
u + 3.5a = 60 .................2
from 1& 2
a = -16 & u=116
velocity after 7 sec = V7
V7 = u + at
=116 - 16*7=4cm/sec
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