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Grade: 12th pass
        
a body travelling with uniform acceleration crosses two points A and B eith velocities 20 m/s and 30m/s respectivly, the speed of the body at mid point of A and B
2 years ago

Answers : (2)

subhabrata ghosh
34 Points
							
Let the acceleration of the car is = a   And the distance between A and B is = d
v-u2=2ad
v=30m/s and u=20m/s
2ad=302-202
ad=(900-400)/2=250
when the car is at the mid point of AB then let the speed of the car is v1
v12-202=2a(d/2)
v12=ad+400=250+400=650
therefore v1 is = 25.4950m/s
:) :)
2 years ago
Soumith Chowdary
48 Points
							Use v^2-u^2=2as where v=30 and u=20 and S is distance between A and B . Substitute S/2 in place of S In equation
						
2 years ago
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