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`        a body travelling with uniform acceleration crosses two points A and B eith velocities 20 m/s and 30m/s respectivly, the speed of the body at mid point of A and B`
2 years ago

subhabrata ghosh
34 Points
```							Let the acceleration of the car is = a   And the distance between A and B is = dv2 -u2=2adv=30m/s and u=20m/s2ad=302-202ad=(900-400)/2=250when the car is at the mid point of AB then let the speed of the car is v1v12-202=2a(d/2)v12=ad+400=250+400=650therefore v1 is = 25.4950m/s:) :)
```
2 years ago
Soumith Chowdary
48 Points
```							Use v^2-u^2=2as where v=30 and u=20 and S is distance between A and B . Substitute S/2 in place of S In equation
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions