Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A body takes time reach the bottomof an inclined plane of angle theta with the horizontal.if the plane is made rough time taken now is 2t.the coefficient of friction of the rough surface is`
2 years ago

Arun
23506 Points
```							Dear studentAngle of incline = θ.Initially it is a smooth surface. Let the mass be m. Gravity g. Initial velocity = u = 0.acceleration down the incline = a = g sinθtime taken = T.So length of incline = s = 1/2 * g sinθ * T²  ...(1)When there is dynamic friction of coefficient = μ, friction force = f = μ N = μm g Cos θa = (sin θ - μ Cos θ) g  Time taken is = 2 TSo we get: s = 1/2 * g (sinθ - μ Cos θ) * (2T)²    ...(2)From (1) and (2) , we getSin θ = (sinθ - μ cosθ) 4μ = Tanθ  * 3/4 RegardsArun (askIITians forum expert)
```
2 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »

### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions