A body stretches a spring by a particular length at the earth’s surface at equator. At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

Question

Deepak Patra · Answer

Sol. At equator, g’ = g – ω^2R …(1) Let at ‘h’ height above the south pole, the acceleration due to gravity is same. Then, here g’ = g (1 – 2h/R) …(2) ∴ g - ω^2 R = g (1 – 2h/R) or 1 - ω^2R/g = 1 2h/R or h = ω^2R^2/2g = (7.3 * 10^-5)^2 * (6400 * 10^3)^2/2 * 9.81 = 11125 N = 10Km (approximately)

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A body stretches a spring by a particular length at the earth’s surface at equator. At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

A body stretches a spring by a particular length at the earth’s surface at equator. At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

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A body stretches a spring by a particular length at the earth’s surface at equator. At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

A body stretches a spring by a particular length at the earth’s surface at equator. At what height above the south pole will it stretch the same spring by the same length? Assume the earth to be spherical.

1 Answers

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