Umakant biswal
Last Activity: 8 Years ago
@ BHAWIKA
i am giving the approach to solve the problem , follow that
here , u=0,
velocity after 2n sec, will be given as v=u+at=0+a*2n.
so, acceleration, a=v/2n
so, velocity after n sec..-
v1=0+at=(v/2n)*n=v/2
now, apply eq. of motion to find d in last n sec
v^2-v1^2=2ad
put values of v,v1 and a
d=[v^2-(v/2)^2]/2*(v/2n)=(3/4)v/(v/n)=3/4*n
i think u can solve it right now .
if not then let me know in this post , i will solve the question fully .
ALL THE BEST ..
