A body starting from rest accelerates at a constant rate a m/s 2 for some time after which it retards at a constant rate b m/s 2 to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by

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Vikas TU · Answer

If u make the graph of velocity vs x in time intervals t1 and t2 respectively, then u would get t1 + t2 = T or v/a + v/b = T v = (ab)*T/(a+b)

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A body starting from rest accelerates at a constant rate a m/s 2 for some time after which it retards at a constant rate b m/s 2 to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by

A body starting from rest accelerates at a constant rate a m/s²for some time after which it retards at a constant rate b m/s² to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by

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A body starting from rest accelerates at a constant rate a m/s 2 for some time after which it retards at a constant rate b m/s 2 to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by

A body starting from rest accelerates at a constant rate a m/s2 for some time after which it retards at a constant rate b m/s2 to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by

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A body starting from rest accelerates at a constant rate a m/s²for some time after which it retards at a constant rate b m/s² to come to rest finally. If the total time elapsed is t sec,the maximum velocity attended by a body is given by