A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is : a)2/ √3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2 How do you get this answer? Thanks!

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Deepakshi · Answer

Object is applying 2N force in the downward direction.Components of T2 will balance it as T1 cos 90=0T2cos30= T1 (1)T2 cos 60= 2 ( from figure)T2 1/2=2T2= 4From 14× cos 30=T14 root3/2=T1T1= 2 root3I suggest u to cross check this answerHope it helps!!!

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A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is : a)2/ √3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2 How do you get this answer? Thanks!

A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is :
a)2/√3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2
How do you get this answer? Thanks!

1 Answers

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A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is : a)2/ √3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2 How do you get this answer? Thanks!

A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is :a)2/√3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2How do you get this answer? Thanks!

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A body of weight 2 kg is suspended as shown in the figure. The tension T1 in the horizontal string(in kg wt) is :
a)2/√3 , b)√3/2 , c)2√3 (answer), d)2 , e)3√2
How do you get this answer? Thanks!