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a body of mass m is projected with initial speed u at an angle ‘o’ with the horizontal.the change in momentum of the body after time t is

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3 years ago

Amrit Raj
46 Points
```							As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘u’ always remains constant ,i.e. in this case ,ux=ucoso, throughout the motion.So change in momentum in horizonal direction is 0(zero).Now analysing the vertical direction motion we know intial velocity in vertical direction uy=usino.After time t,vy=usino-gt,(using eq. of motion ,v=u+at)Thus, Change in momentum in vertical direction =m.vy-m.uy =m.(usino-gt)-(m.usino)=-mgtNOTE: Take the vector consideration.
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3 years ago
605 Points
```							Dear student,Please find the answer to your question. As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘u’ always remains constant ,i.e. in this case ,ux=ucosQ, throughout the motion.So change in momentum in horizonal direction is 0(zero).Now analysing the vertical direction motion we know intial velocity in vertical direction uy=usinQ.After time t,vy=usinQ-gt,(using eq. of motion ,v=u+at)Thus, Change in momentum in vertical direction =m.vy-m.uy = m.(usinQ – gt) – (m.usinQ)= – mgt Thanks and regards,Kushagra
```
one month ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions