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Grade: 12

                        

a body of mass m is projected with initial speed u at an angle ‘o’ with the horizontal.the change in momentum of the body after time t is

3 years ago

Answers : (2)

Amrit Raj
46 Points
							
As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘u’ always remains constant ,i.e. in this case ,ux=ucoso, throughout the motion.So change in momentum in horizonal direction is 0(zero).
Now analysing the vertical direction motion we know intial velocity in vertical direction uy=usino.
After time t,vy=usino-gt,(using eq. of motion ,v=u+at)
Thus, Change in momentum in vertical direction =m.vy-m.u
=m.(usino-gt)-(m.usino)
=-mgt
NOTE: Take the vector consideration.
  
3 years ago
Kushagra Madhukar
askIITians Faculty
605 Points
							
Dear student,
Please find the answer to your question.
 
As we know that a projectile motion is a combination to horizontal and verticle motion.The vetical component of intial velocity ‘u’ always remains constant ,i.e. in this case ,ux=ucosQ, throughout the motion.So change in momentum in horizonal direction is 0(zero).
Now analysing the vertical direction motion we know intial velocity in vertical direction uy=usinQ.
After time t,vy=usinQ-gt,(using eq. of motion ,v=u+at)
Thus, Change in momentum in vertical direction =m.vy-m.u
= m.(usinQ – gt) – (m.usinQ)
= – mgt
 
Thanks and regards,
Kushagra
one month ago
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