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The centripetal acceleration ac=k2rt2 or v2/r = k2rt2
Or v= krt and if we differentiate we get tangential acceleration =kr
Work will be done by tangential force and Power = Ft.v.cos0° which is equal to mat(krt) = mk2r2t
Thanks & Regards,
Vasantha Sivaraj,
askIITians faculty
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