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A body of mass M as shown in figure with a small disc m placed on it rests on a smooth horizontal plane. The disc is set in motion in horizontal direction with velocity v. To what height relative to initial level will the disc rise after breaking off the body M? There is no friction in environment.
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The initial kinetic energy of the system=mv2/2After collision the energy is distributed in the the inverse of mass ratio of the two bodiesThat isthe body with less mass will gain more energyNow, assuming it to be an elastic collision:M/(M+m)*(initial kinetic energy)=mghM/(m+M)*(mv2)/2=mghSolving them we will geth=Mv2/2g(M+m)
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