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A body of mass M as shown in figure with a small disc m placed on it rests on a smooth horizontal plane. The disc is set in motion in horizontal direction with velocity v. To what height relative to initial level will the disc rise after breaking off the body M? There is no friction in environment.
A body of mass M as shown in figure with a small disc m placed on it rests on a smooth horizontal plane. The disc is set in motion in horizontal direction with velocity v. To what height relative to initial level will the disc rise after breaking off the body M? There is no friction in environment.

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3 years ago

Naredra gandhi
13 Points
```							Plzzzz.plzzzzz..plzzzzz.anwer this question...its reallly important....for me....so plzzz answer....plzzz plzzz plzzzz....any one...plzzz answer..
```
3 years ago
Arnab Mahapatra
26 Points
```							The initial kinetic energy of the system=mv2/2After collision the energy is distributed in the the inverse of mass ratio of the two bodiesThat isthe body with less mass will gain more energyNow, assuming it to be an elastic collision:M/(M+m)*(initial kinetic energy)=mghM/(m+M)*(mv2)/2=mghSolving them we will geth=Mv2/2g(M+m)
```
2 years ago
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### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions